Ajax中二级联动菜单的实现原理是什么
Ajax中二级联动菜单的实现原理是什么,相信很多没有经验的人对此束手无策,为此本文总结了问题出现的原因和解决方法,通过这篇文章希望你能解决这个问题。

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index.jsp:
<%@ page language="java" pageEncoding="UTF-8"%>二级菜单联动演示
SelectServlet:
package com;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/***
*
* @author zdw
*
*/
public class SelectServlet extends HttpServlet
{
private static final long serialVersionUID = 1L;
public SelectServlet()
{
super();
}
public void destroy()
{
super.destroy();
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
// response.setCharacterEncoding("GBK");
response.setContentType("text/xml");
response.setHeader("Cache-Control", "no-cache");
request.setCharacterEncoding("GBK");
response.setCharacterEncoding("UTF-8");
String targetId = request.getParameter("id").toString();
System.out.println(targetId);
// 获得请求中参数为id的值
String xml_start = "";
String xml_end = " ";
String xml = "";
if (targetId.equalsIgnoreCase("0"))
{
xml = "";
} else if (targetId.equalsIgnoreCase("1"))
{
xml = "";
xml += "";
xml += "";
xml += "";
} else if (targetId.equalsIgnoreCase("2"))
{
xml = "";
xml += "";
xml += "";
xml += "";
} else
{// 如果是3,则返回下面的字符
xml = "";
xml += "";
xml += "";
xml += "";
}
String last_xml = xml_start + xml + xml_end;
response.getWriter().write(last_xml);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
doGet(request, response);
}
public void init() throws ServletException
{
}
}
web.xml:
SelectServlet com.SelectServlet SelectServlet /select index.jsp
看完上述内容,你们掌握Ajax中二级联动菜单的实现原理是什么的方法了吗?如果还想学到更多技能或想了解更多相关内容,欢迎关注创新互联行业资讯频道,感谢各位的阅读!
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