LeetCode226:InvertBinaryTree二叉树反转
题目

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226. Invert Binary Tree
QuestionEditorial Solution
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Total Accepted: 109341
Total Submissions: 230799
Difficulty: Easy
Invert a binary tree.
4 / \ 2 7 / \ / \ 1 3 6 9
to
4 / \ 7 2 / \ / \ 9 6 3 1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
TreeNode *p,*q;
p = NULL;
q = NULL;
if(root != NULL)
{
p = root->left;
q = root->right;
root->left = q;
root->right = p;
invertTree(root->left);
invertTree(root->right);
}
return root;
}
};
新闻标题:LeetCode226:InvertBinaryTree二叉树反转
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